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Week 4 - Neutron-Star Cooling and Heating [3] [5]
Summary
Neutron stars are born in the fiery explosion of a supernova. Although
they are cold in the sense that the Fermi temperature is much greater than
the thermodynamic temperature except in the outermost layers, neutron stars
radiate like any hot bodies. In fact their interiors and crusts radiate
neutrinos and their surfaces radiate soft x-rays. These soft x-rays are some
of the few direct data that we get from neutron stars.
Reading List
- ``Surface X-Ray Emission from Neutron Stars''
[
ADS,
APS,
PDF
]
REF: Chiu, H., Salpeter, E. E. 1964, Physical Review Letters, 12, 413-415 .
- ``Analytical Models of Neutron Star Envelopes''
[
ADS,
PDF
]
REF: Hernquist, L., Applegate, J. H. 1984, ApJ, 287, 244 .
- ``Almost Analtyic Models of Ultramagnetized Neutron Star Envelopes''
[
ADS,
astro-ph/9805175,
PostScript,
PDF ,
Java
]
REF: Heyl, J. S., Hernquist, L. 1998, Mon. Not. Royal Astr. Soc., 300, 599 .
Problem Set
Problem 1 - Thermodynamics and General Relativity 
In general relativity if two bodies are in thermodynamic equilibrium,
We can exploit this relationship along with Kirchoff's law to derive some
interesting facts about how light travels from a neutron star to our
telescopes. You can experiment with neutron-star lensing with
this Java Applet.
-
Because everything is in thermodynamic equilibrium, we can safely
assume that the neutron star of mass M and radius R emits as a
blackbody at a temperature T. Calculate the total power emitted
from the neutron star surface in the frame of the neutron star
surface.
-
Calculate the total power received at infinity. Let the redshift of the
surface be z.
-
Let the space surrounding the star be filled with blackbody radiation
in thermal equilibrium with the surface of the neutron star. You can
imagine that the neutron star is in a gigantic thermos bottle.
Let T∞ be the temperature of this blackbody radiation
measured at infinity (i.e. z=0). What is T∞?
Now here comes Kirchoff's law: in thermodynamic equilibrium a body emits as
much as it receives.
-
How much power does the neutron star absorb from the blackbody at infinity?
This is the product of the surface area of the neutron star with the flux
per unit area of the blackbody radiation.
A conundrum: compare the answer to (2) with the answer to (4). They differ.
Does the neutron star cool down because (2) is greater than (4)?
The neutron star can't cool down because it is already in equilibrium, so one
of our assumptions must be wrong.
-
It turns out that the most innocuous sounding assumption is incorrect. The power that the neutron star absorbs is the product of its apparent surface area
with the flux per unit area of the blackbody radiation.
Let the apparent radius be R∞ and recalculate the answer
to (4).
-
Equate (2) and (5) and solve for R∞.
R∞ ≠ R because in the vicinity of a neutron star light does
not travel in a straight line. One can also derive the value of
R∞ by solving for a null geodesic that is tangent to the
surface of the neutron star.
-
What is the minimum value of R∞ for a constant value of M? You
will need to know that
1+z = |
1 (1 - 2 G M/R c2)1/2 |
What is the value of R? Call this radius Rγ.
-
Prove the size of the image of the neutron star must decrease or remain the
same as the radius of the neutron star decreases. Use the fact that rays
that we ultimately see remain outgoing throughout their journey to us
(otherwise by symmetry they would hit the surface a second time).
-
What happens to the size of the image of the star if the radius of the star
is less that Rγ?
-
The calculation of the apparent radius of the star from thermodynamics
hinges on the assumption that the outgoing flux from the surface
reaches infinity. For R < Rγ, the size of the image
no longer increases while thermodynamics says it should, so we must
conclude that for radii less than Rγ initially
outgoing photons can become incoming photons.
From these arguments and spherical symmetry speculate what might happen to a
photon emitted precisely at Rγ tangentially, i.e. neither
ingoing or outgoing.
-
Calculate how much radiation a star whose radius is less
than Rγ will absorb.
The answer to (11) falls short of (2) again. We know that the star
can't heat up, so an assumption must be wrong. Within Rγ
not every photon emitted can escape to infinity, many photons
return and hit the surface.
-
Using the answers to (2) and (11), calculate the fraction of the
outgoing photon flux emitted from the surface that manages to escape.
-
Use the fact that a blackbody emits isotropically to determine the
opening angle of the cone into which the escaping photons are emitted.
This region is symmetric around the radial direction.
-
Pat yourself on the back. You have derived many of the quirky things about
the Schwarschild metric (the metric that surrounds a spherically symmetric
mass distribution). List the key assumptions that you have made to
make this derivation work.
Problem 2 - Light-Envelope Neutron-Star Cooling 
The presence of hydrogen in the atmosphere of a neutron star strongly affects
the emission of the surface of the star and possibly how the star cools.
-
Calculate the maximum possible density of pure degenerate ionized
hydrogen gas (non-degenerate protons and degenerate electrons). What
happens above this density?
-
Assume that the electrons dominate the pressure, what is the pressure at
this critical density?
-
Assume that the gravitational acceleration is constant in this thin layer
and is given by gs,141014 cm s-2. What is
the column density of the layer?
- Assume that the stellar radius is
R6 106 cm.
How much hydrogen can you pile onto a neutron star?
-
Assume that the cross section to x-rays per electron-proton pair
is given by the Thomson cross-section. What is the column density
of an optically thick layer of hydrogen (τ=1)?
-
The conductivity of the surface layers of a neutron star is inversely
proportional to the atomic number of the nuclei. How does the
surface luminosity of neutron star change if you pour hydrogen
onto its surface?
Last modified: Thursday, 08 April 2010 14:15:29
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