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Week 2 - Rotation-Powered Neutron Stars
Problem Set
Problem 1 - Spinning Neutron Stars 
We will estimate how quickly we would expect neutron stars to spin, how
much energy is stored in their spin and other interesting facts about spinning
neutron stars.
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The sun rotates every 24-30 days depending on latitude. How quickly would it
rotate if it were compressed to 10km in radius while conserving its angular momentum? Its current radius is 7 x 1010 cm.
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How fast could a neutron star rotate without breaking up? Consider the neutron
star to be 1.4
and have a radius of 10 km and compare the
centripetal acceleration of a bit of material on the surface to the
gravitational acceleration.
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How much angular momentum and rotational energy does a neutron star have? Use
and a spin period of break-up, 1.6 ms, 33 ms and 6 s.
Answer for Problem 1
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The angular momentum of a rotating body is proportional to M R2 P-1, so if R deceases by a factor of 7 x 104, its period
will decrease by the square of that factor, so P ≈ 0.44 ms.
- Breaking up is hard to do.
G M
R2
|
= |
4 π2 R
P2
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so
P2= |
4 π2 R3
G M
|
Substituting the numbers yields about 0.46 ms.
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First we will calculate I. The formula above yields 1 x
1045 g cm2. The angular momentum is
simply I Ω and the energy is ½ I &Omega2
L = 6 x 1045 P-1 erg s and E = 2 x 1046 P-2 erg where P is the period in seconds.
P | L | E |
0.44ms | 1.4 x 1049 | 1 x 1053 |
1.6ms | 4 x 1048 | 8 x 1051 |
33ms | 2 x 1047 | 2 x 1049 |
6s | 1 x 1045 | 6 x 1044 |
Problem 2 - Original Spin 
If you know the age of a neutron star, its current period and its period
derivative, you can estimate its original spin.
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Using the results from the lectures, derive a formula for P0 in terms
of the age, current period and period derivative of a pulsar.
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The table below lists pulsars that are associated with historical supernovae.
Complete the table by calculating the original spin of these neutron stars.
Name |
Age [yr] |
Period [s] |
P-dot [10-15 s s-1] |
P0 [s] |
B0531-21 |
949 |
0.0331 |
422.69 |
|
B0540-69 |
1000 |
0.050 |
480 |
|
B1951+32 |
64000 |
0.0395 |
5.8 |
|
J0205+6449 |
822 |
0.06568 |
193 |
|
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Why do we know the age of the first and last pulsars so accurately?
Answer for Problem 2
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P0=(P2-2 τ P P-dot)1/2
= P (1-2 τ/T)1/2
where &tau is the age of the pulsar and T is the characteristic age,
T=P/P-dot. If τ << T, then the pulsar's period hasn't changed much
since it was born (which makes a whole lot of sense).
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Filling out the table with the formula:
Name |
Age [yr] |
Period [s] |
P-dot [10-15 s s-1] |
P0 [s] |
B0531-21 |
949 |
0.0331 |
422.69 |
0.016 |
B0540-69 |
1000 |
0.050 |
480 |
0.031 |
B1951+32 |
64000 |
0.0395 |
5.8 |
0.025 |
J0205+6449 |
822 |
0.06568 |
193 |
0.060 |
Notice that none of them started their dipole spin-down at zero period. This
could mean that the neutron stars were born spinning slowly or perhaps
something else slowed them down at the beginning like gravitational radiation.
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They are associated with historical supernovae that were first seen on
July 4, 1054 (now the Crab Nebula or M1) and August 6, 1181
(now the SNR 3C 58).
Last modified: Thursday, 08 April 2010 14:15:28
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