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Why is the price right?

Returning to our old arbitrage argument, here is what the buyer of the derivative can do if the price is set at p', which is less than the value p as specified by equation [*].
1.
he would buy 1 unit12 of derivative at time zero and pay p' dollars to the seller.
2.
also at time zero, sell the portfolio with content $(\phi_{0},\psi_{0})$ and receive an amount p.
3.
put the difference p-p'>0 in a bank and at time T, he would get $(p-p^{'})\exp(rT)$ dollars.
4.
at time T, he would buyback the original portfolio, using money from the worth of the derivative at time T, no matter whether the stock price is up or down!13
5.
the conclusion is: using this method, the buyer loses nothing by buying the derivative; moreover, he also gains a risk free profit of $(p-p^{'})\exp(rT)$ dollars at time T!
Obviously, we can also reverse the argument if p'>p; therefore p'must be equal to p in order to prevent arbitrage.

Birger Bergersen
1998-12-22